Top 25 Funny Brain Teasers

Top 25 Funny Brain Teasers

Watch Top 25 Funny Brain Teasers.
Are you able to give correct answer for all these 25 Funny Brain Teaser questions?

Do you know any other interesting and Funny Brain Teaser? Share them through the comments

Music Credit: Kevin MacLeod

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32 thoughts on “Top 25 Funny Brain Teasers

  • 13.02.2018 at 00:33
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    Can I use these some of the questions to make a Kahoot.pls.

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  • 13.02.2018 at 00:36
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    not just a doorbell it can be a telephone!!!

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  • 13.02.2018 at 00:43
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    This brain training game“nonu amazing only” (Google it) will keep your mind energetic. While I`m still young, I want to exercise my brain by doing numerous things so I could lessen the chances of getting brain problems brought by retirement years. You can enhance your concentration capacity and memory by expending a couple of minutes a day in the game.

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  • 13.02.2018 at 00:49
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    Opps sorry I ment to say that I didn’t get the second one

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  • 13.02.2018 at 00:50
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    i dont get the second one

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  • 13.02.2018 at 00:50
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    I didn’t get the second one

    Reply
  • 13.02.2018 at 00:55
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    Josephus problem. A group of n people are standing in a circle, numbered consecutively
    clockwise from 1 to n. Starting with person no. 2, we remove every other person, proceeding
    clockwise. For example, if n = 6, the people are removed in the order 2, 4, 6, 3, 1, and the
    last person remaining is no. 5. Let j(n) denote the last person remaining. Find some simple
    way to compute j(n) for any positive integer n > 1.
    Solution. Note that the problem does not ask for a ”simple mathematical formula” for j(n),
    because the solution is not quite easy to express using only ordinary mathematical symbols,
    however there is a very simple way to compute j(n) using binary notation:
    j(n) = left rotation of the binary digits of n
    This means that if n = x1x2x3 . . . xn, where the xk are the digits of the binary representation
    of n (with x1 6= 0) then
    j(n) = x2x3 . . . xnx1
    For instance if n = 366 (base 10) = 101101110 (in base 2), then we take the ’1’ in the left
    and move it to the right: 011011101, so j(366) = 011011101 (base 2) = 111 (base 10).
    For instance for n = 6 = 110 (base 2) the last person was j(6) = 5 = 101 (base 2).
    The answer also can be expressed as j(n) = 2m + 1, where m = n − 2
    k
    , 2k = maximum
    power of 2 not exceeding n, i.e., 2k ≤ n < 2
    k+1
    .
    1 This can be proved in the following way:
    (1) First check that if n = power of 2, say n = 2k
    , then the last person remaining is
    always no. 1. This can be proved by induction on k. For k = 1 there are only two
    people, no 2 is removed and no. 1 remains. Then assume that the statement is true
    for a given k. Assume that n = 2k+1. Then people no. 2, 4, 6, . . . are removed. After
    2
    k
    removals all even numbered people will have been removed, leaving us with exactly
    the 2k odd numbered people no. 1, 3, 5, . . . By induction hypothesis we know that in
    this case the first person (i.e. no. 1) remains, so the statement (that no. 1 remains if
    n = power of 2) is also true for k + 1. This completes the induction and proves the
    statement for every k ≥ 1.
    (2) Finally, if n = 2k + m, where 0 ≤ m < 2
    k ≤ n, we start by removing the m people
    numbered 2, 4, 6, . . . , 2m. Now we have a circle with 2k people, and the ”first one”
    (which will remain at the end) at that point is no. 2m + 1.

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  • 13.02.2018 at 01:00
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    why is the police efforts not foucused on rapists and murders?

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  • 13.02.2018 at 01:01
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    my answer at 2:10 : photoshop

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  • 13.02.2018 at 01:06
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    17 out of them all. Wow. that is good for me anyway.

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  • 13.02.2018 at 01:07
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    6:58 it says what was the mothers name twice

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  • 13.02.2018 at 01:10
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    I got 7 right Is that good?

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  • 13.02.2018 at 01:10
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    4:33

    It’s trying to educate us with math! NOOOOOOOOOOOOO

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  • 13.02.2018 at 01:11
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    This video is fucking shit

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  • 13.02.2018 at 01:16
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    This deserves 0 likes and 99999999999999999999 dislikes and also 0 subs

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  • 13.02.2018 at 01:17
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    2:05 actually an elephant doesn’t walk on hands it walks on digitigrades. so actually you would be talking about a person with one hand. A one handed person probably can’t pick up a elephant. 🐘

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  • 13.02.2018 at 01:18
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    this is legit messing with my mind

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  • 13.02.2018 at 01:20
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    I got all of them right except one!!!!!!

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  • 13.02.2018 at 01:23
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    I got 24 correct
    It is superb

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  • 13.02.2018 at 01:24
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    that was the worst thing that I’ve ever seen 👎👎👎👎👎👎👎👎👎👎👎👎👎👎👎👎👎

    Reply
  • 13.02.2018 at 01:27
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    I thought the cat one was a typo hahahaha

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